-16x^2+48x+448=0

Solution for -16x^2+48x+448=0 equation:

-16x^2+48x+448=0

a = -16; b = 48; c = +448;
Δ = b2-4ac
Δ = 482-4·(-16)·448
Δ = 30976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{30976}=176$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-176}{2*-16}=\frac{-224}{-32}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+176}{2*-16}=\frac{128}{-32}
=-4
$